X=-16x^2+128x+100

Solution for X=-16x^2+128x+100 equation:

X=-16X^2+128X+100

We move all terms to the left:

X-(-16X^2+128X+100)=0

We get rid of parentheses

16X^2-128X+X-100=0

We add all the numbers together, and all the variables

16X^2-127X-100=0

a = 16; b = -127; c = -100;
Δ = b2-4ac
Δ = -1272-4·16·(-100)
Δ = 22529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-127)-\sqrt{22529}}{2*16}=\frac{127-\sqrt{22529}}{32}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-127)+\sqrt{22529}}{2*16}=\frac{127+\sqrt{22529}}{32}
$